x^2-3x-2=0.3

Solution for x^2-3x-2=0.3 equation:

x^2-3x-2=0.3

We move all terms to the left:

x^2-3x-2-(0.3)=0

We add all the numbers together, and all the variables

x^2-3x-2.3=0

a = 1; b = -3; c = -2.3;
Δ = b2-4ac
Δ = -32-4·1·(-2.3)
Δ = 18.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{18.2}}{2*1}=\frac{3-\sqrt{18.2}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{18.2}}{2*1}=\frac{3+\sqrt{18.2}}{2}
$